Operator Norm, Intuitively

If $X$ and $Y$ are normed vector spaces, a linear map $T:X\to Y$ is said to be bounded if $\|T\| <\infty$ where $$\|T\|=\sup_{\underset{x\neq 0}{x\in X}}\left\{\frac{|T(x)|}{|x|}\right\}.$$ (Note that $|T(x)|$ is the norm in $Y$ whereas $|x|$ is the norm in $X$.) One can show that this is equivalent to $$\|T\|=\sup_{x\in X}\{|T(x)|:|x|=1\}.$$ So intuitively (at least in two dimensions), we can think of $\|T\|$ this way:        

Related Posts

English is Not Commutative

The Back Pocket

Why are Noetherian Rings Special?

The Back Pocket

One Unspoken Rule of Algebra

The Back Pocket

Need to Prove Your Ring is NOT a UFD?

The Back Pocket
Leave a comment!